Chemical Reaction Engineering
With multiple reactions, either molar flow or number of moles must be used in setting up the balance equations (no conversion!)
Mole balance: Write balance for each species i=1 to N
dWdFi=ri′
Rate law
−rA′=kCAαCBβ;−arA′=−brB′=crC′=drD′
Stoichiometry Ci=(1+ϵX)CA0(Θi+νiX)(P0P)(TT0)
Pressure: dWdP=−2pα(T0T)FT0FT
Total molar flow rate: FT=∑i=1NFi
Combine:
Collate all equations from steps 1 to 3 to yield a system of equations
Evaluate:
Use ODE solver to solve the system of equations obtained in step 4.
Competing reactions
Reactant is consumed by two different pathways to form different products
AkX1DAkX2U
Examples
Ethylene oxidation
CX2HX4+OX2CX2HX4+OX2CX2HX4O2COX2+2HX2Oethylene oxidecomplete combustion
Fischer Tropsch synthesis
CO+3HX2CO+2HX2kX1CHX4+HX2OkX2[CXnHX2n]Xn+HX2O
Consecutive reactions
Reactions where reactant forms an intermediate product, which reacts further to form another product.
AkX1DkX2U
Example
CX2HX4O+NHX3(HOCHX2CHX2)NHX2+CX2HX4O(HOCHX2CHX2)X2NH+CX2HX4O(HOCHX2CHX2)NHX2desired product(HOCHX2CHX2)X2NH(HOCHX2CHX2)X3N(mono ethanolamine)(di ethanolamine)(tri ethanolamine)
Reactions that occur at the same time
Neither the products nor the reactants react with themselves or one another
AkX1DCkX2U
Example: Cracking of crude oil
Hundreds of reactions
CX15HX32CX8HX18CX12HX26+CX3HX6CX6HX14+CX2HX2
Multiple reactions involving a combination of series, parallel, and/or independent reactions
A+BA+CEkX1C+DkX2EkX3G
Example: Formation of butadiene from ethanol
CX2HX5OHCX2HX5OHCX2HX4+CHX3CHOCX2HX4+HX2OCHX3CHO+HX2CX4HX6+HX2O
Parallel reactions AADu←desired product←undesired byproduct
Series reactions Adesired productBU
Minimize formation of U and maximize formation of D
Greater the amount of U ← lower production of desired product, higher cost of separation ← lower profits
SD/U=rUrD=rate of formation of Urate of formation of D
SˉD/U=FUFD=Exit molar flow rate of UExit molar flow rate of D
For CSTR:
FD=rDV
FU=rUV
∴FD/FU=rD/rU=SD/U=SˉD/U
For batch reactor:
SˉD/U=ND/NU
ND,NU: Number of moles of D and U at the end of the reaction.
Ratio of the reaction rate of a given product to the reaction rate of key reactant A
YD=−rArD=Rate of consumption of ARate of formation of D
Ratio of moles of product formed at the end of the reaction to the number of moles of the key reactant A, that have been consumed.
YˉD=For CSTRFA0−FAFD=For batch reactorNA0−NAND
Gives insight into problem
Often conflicts with selelctivity
Ideal world ⇒ make as much D as possible simultaneously minimize U
Practical experiece ⇒ Greater the conversion, more the undesired product
Not used in solving multiple reaction problems, but calculated later for analysis
For species A XA=Flow systemFA0FA0−FAXA=Batch systemNA0NA0−NA
For species B XB=Flow systemFB0FB0−FBXB=Batch systemNB0NB0−NB
Derive expression for conversion for a semibatch system where B is fed to A
Number each and every reaction separately.
Mole balance on each and every species.
Fj0−Fj+∫VrjdV=dtdNj
For every reaction write rate law. Calculate the net rate of reaction and relative rates
For component j: rj=∑i=1Nri,j
Stoichiometry
Combine:
Collate all equations from steps 2 to 4 to yield a system of equations
Evaluate:
Use ODE solver to solve the system of equations obtained in step 4.
Can be applied to parallel, series, independent, and complex reactions.
For liquid systems concentration is usually preferred variable for mole balance.
Consider two competing reactions
ADAU(desired)(undesired)rD=kDCAα1rU=kUCAα2
Net rate of disappearance of A
−rA=rD+rU=kDCAα1+kUCAα2
SD/U=rUrD=kUkDCAα1−α2
α1, α2 are positive orders
α1−α2=a
SD/U=kUkDCAa
To maximize selectivity we wan to carry out the reaction in a manner that will keep CA as high as possible during the reaction.
Use PFR or batch reactor
Gas phase: Use high pressure, run without inerts
Liquid phase: minimize diluent
α2−α1=b
SD/U=kUkDCAb1
To maximize selectivity we wan to carry out the reaction in a manner that will keep CA as low as possible during the reaction.
Use CSTR or dilute feed stream
Recycle reactor
Need information on activation energy
Sensitivity to temperature for fixed concentrations (CAa is constant)
SD/U≈kUkD=AUADe−[(ED−EU)/RT]
ED>EU
ED<EU
kU increases more rapidly than kD with increase in temperature
Reaction should be carried out at lower temperature to maximize SD/U
The temperature should not be very low as it might affect reaction extent. Reaction may not proceed at low temperature.
Consider two competing parallel reactions
A+BDA+BU(desired)(undesired)rD=kDCAα1CBβ1rU=kUCAα2CBβ2
Net rate of disappearance of A
−rA=rD+rU=kDCAα1CBβ1+kUCAα2CBβ2
Selectivity
SD/U=rUrD=kUkDCAα1−α2CBβ1−β2
α1−α2=a;β1−β2=b
SD/U∝CAaCBb
Use high CA,CB
Configurations:
SD/U∝CBbCAa
Use high CA, low CB
Configurations:
α1−α2=a;β1−β2=b
SD/U∝CBbCAa
Use high CB, low CA
Configurations:
SD/U∝CAaCBb1
Use low CA,CB
Configurations:
CSTR
Feed diluted streams with inerts
Low pressure (gas phase)
Tubular reactor with large recycle ratio
Can be used for highly exothermic reactions. The recycle stream is cooled and returned to the reactor to dilute and cool inlet stream.
Such configuration helps in avoiding hotspots and runaway reactions.
The most important variable is time
Consider: AkX1BkX2C.
B is the desired product
If k1≪k2: First reaction is slow
If k1≫k2: First reaction is fast
If reaction is allowed to proceed for a long time, desired product B will be converted to undesired product C.
Accuracy of prediction for time required to carry out the reaction is vital.
Consider the reaction
AkX1BkX2C.
B is the desired product, C is waste product.
We are interested in
Number of reactions
The series reaction can be written as two reactions
AB;−r1A=k1CA.
BC;−r2B=k2CB.
Mole balance dtdNi=riV
For constant volume batch reactor
dtdCA=rA=−k1CA(1)
dtdCB=rB=k1CA−k2CB(2)
dtdCC=rC=k2CC(3)
Chemical Reaction Engineering